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Sagot :
Answer:
[tex] {x}^{2} + 6x - 8 - 3x + 2 - 3 {x}^{2} \\ = (1 - 3) {x}^{2} + (6 - 3)x + 2 - 8 \\ = - 2 {x}^{2} + 3x - 6[/tex]
4x+4+2x+2-8x
=(4+2-8)x +4+2
=-2x+6
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