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Sagot :
Given:
In rhombus RSTU, [tex]m\angle RUV=(10x-23)^\circ[/tex] and [tex]m\angle TUV=(3x+19)^\circ[/tex].
To find:
The [tex]m\angle RST[/tex].
Solution:
We know that, diagonals of a rhombus are angle bisector. So,
[tex]m\angle RUV=m\angle TUV[/tex]
[tex](10x-23)^\circ=(3x+19)^\circ[/tex]
[tex]10x-23=3x+19[/tex]
Isolating variable terms, we get
[tex]10x-3x=23+19[/tex]
[tex]7x=42[/tex]
Divide both sides by 7.
[tex]x=\dfrac{42}{7}[/tex]
[tex]x=6[/tex]
Now,
[tex]m\angle RUV=(10x-23)^\circ[/tex]
[tex]m\angle RUV=(10(6)-23)^\circ[/tex]
[tex]m\angle RUV=(60-23)^\circ[/tex]
[tex]m\angle RUV=37^\circ[/tex]
And,
[tex]m\angle TUV=(3x+19)^\circ[/tex].
[tex]m\angle TUV=(3(6)+19)^\circ[/tex]
[tex]m\angle TUV=(18+19)^\circ[/tex]
[tex]m\angle TUV=37^\circ[/tex]
Now,
[tex]m\angle RUT=m\angle RUV+m\angle TUV[/tex]
[tex]m\angle RUT=37^\circ+37^\circ[/tex]
[tex]m\angle RUT=74^\circ[/tex]
We know that opposite angles of a rhombus are equal.
[tex]m\angle RST=m\angle RUT[/tex]
[tex]m\angle RST=74^\circ[/tex]
Therefore, the measure of angle RST is [tex]74^\circ[/tex].
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