Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer: The two consecutive numbers are 6 and 7.
Step-by-step explanation:
Here the problem is that the logarithm is not the natural logarithm we usually use, to return to the natural logarithm, we can use the next property:
Logₐ(x) = Ln(x)/Ln(a)
Then:
Log₂(75) = Ln(75)/Ln(2)
Now we can do these calculations.
Ln(75)/Ln(2) = 4.317/0.693 = 6.229
Now we want to find two consecutive integers, n and m, such that:
n < 6.229 < m
Because they are consecutive numbers, we must have:
m = n + 1
then:
n < 6.229 < n + 1
The only possibility here is:
n = 6
n + 1 = 7
The two consecutive numbers are 6 and 7.
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.