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a scooter weighs 120kg. Brakes are applied so that wheels stop rolling and start skidding. Find the force of friction if the coefficient of friction is 0.4

Sagot :

LammettHash

Assuming the scooter is moving horizontally on a flat surface, then by Newton's second law, the vertical forces (the normal force and the scooter's weight) cancel out:

n - w = 0

n = w

n = (120 kg) g = 1176 N

(where g = 9.8 m/s²)

Then the friction force has a magnitude of

f = µ n

where µ is the coefficient of kinetic friction, so that

f = 0.4 (1176 N) = 470.4 N ≈ 470 N

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