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help meeeeeeeeeeee
Simplify. Assume that all variables are positive.
√99x^17

Sagot :

3x^8 square root of 11x

Answer:

[tex]3x^8\sqrt{11x}[/tex]

Step-by-step explanation:

[tex]\sqrt{99x^{17}}[/tex]

First we have to break the 99 up into 9 and 11. Since 9 is a perfect square, it'll come out perfect. Then for the x to the power of 17 we will make the exponent into an even number by taking one x away.

[tex]\sqrt{99x^{17}}\\\sqrt{9x^{16}}\sqrt{11x}[/tex]

So after we have this simplify the perfect square and don't touch the non-perfect ones.

[tex]\sqrt{99x^{17}}\\\sqrt{9x^{16}}\sqrt{11x}\\3x^8\sqrt{11x}[/tex]

So that's it!

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