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compare between x=ab+1 and y=a+b

Sagot :

Answer:

[tex]y = a + b \\ a = y - b = = = > (i) \\ x = ab + 1 \\ x = (y - b)b + 1 \\ x = yb - {b}^{2} + 1 \\ yb = x + {b}^{2} - 1 \\ y = \frac{1}{b} (x + {b}^{2} - 1)[/tex]

Answer:

ab=x-1

a=y-b

x-1=(y-b)b

X-1/y-b=b

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