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Sagot :
Answer:
9 Litre of 100% acid, 27 Litre of 20% acid solution
Step-by-step explanation:
We know that 1 = 100% while
0.2 = 20%
We assume that x is volume of 100% solution, while y is volume of 20% solution.
x + 0.2y = (36×40/100)
x+0.2y= 14.4--------eqn(1)
x+y=36-------eqn(2)
x=36-y------eqn(3)
Input eqn(2) into 1 we have
(36-y)+0.2y= 14.4
-y+0.2y=14.4-36
-0.8y= 21.6
y=21.6/0.8
y=27
Hence, 27 Litre of 20% acid is required
From eqn(3) we can find value of x
x = 36-27
9 Litre of 100% acid is required
9 Litre of 100% acid, 27 Litre of 20% acid
Hence, the laboratory technician can combine a batch of 9 Litre of 100% acid, 27 Litre of 20% acid an acid solution that is pure acid with another that is 20% to get the desired concentration
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