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Sagot :
Answer:
6.68 g MgSO₄
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Chemistry
Aqueous Solutions
- Molarity = moles of solute / liters of solution
Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
Step 1: Define
0.965 L
0.0575 M
Step 2: Identify Conversions
Molar Mass of Mg - 24.31 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of MgSO₄ - 24.31 + 32.07 + 4(16.00) = 120.38 g/mol
Step 3: Find MgSO₄
- Substitute [M]: 0.0575 M = x / 0.965 L
- Isolate x: 0.055488 mol MgSO₄ = x
- Rewrite: x = 0.055488 mol MgSO₄
Step 4: Convert
[tex]\displaystyle 0.055488 \ mol \ MgSO_4(\frac{120.38 \ g \ MgSO_4}{1 \ mol \ MgSO_4} )[/tex] = 6.67959 g MgSO₄
Step 5: Check
We are given 3 sig figs as our lowest. Follow sig fig rules and round.
6.67959 g MgSO₄ ≈ 6.68 g MgSO₄
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