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Solve for f: ax+3b=2f ​

Sagot :

rparam676

Final Answer: [tex]f = \frac{ax}{2} + \frac{3b}{2}[/tex]

Steps/Reasons/Explanation:

We will be trying to rewrite the equation. To do this we will move [tex]2f[/tex] to the left. Then, we will move [tex]ax + 3b[/tex] to the right.

Question: Solve for [tex]f[/tex]: [tex]ax + 3b = 2f[/tex].

Step 1: Rewrite the equation.

[tex]2f = ax + 3b[/tex]

Step 2: Divide each term by [tex]2[/tex] and simplify.

[tex]\frac{2f}{2} = \frac{ax}{2} + \frac{3b}{2}[/tex]

Step 3: Cancel out the common factor of [tex]2[/tex].

[tex]\frac{Cancel 2 f}{Cancel 2} = \frac{ax}{2} + \frac{3b}{2}[/tex]

Step 4: Divide [tex]f[/tex] by [tex]1[/tex].

[tex]f = \frac{ax}{2} + \frac{3b}{2}[/tex]

~I hope I helped you :)~

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