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25 POINTS AND BRAINLIEST! PLEASE HELP ME !!! answer all questions please !

Trey made a scale drawing of a microchip using a scale of 2 inches to 1 centimeter. His drawing was an enlargement that depicted the chip as 6
inches long and 4 inches wide. However, the drawing isn't big enough to clearly show all of the chip's components. So he wants to make the
drawing larger
Complete the steps below to figure the dimensions of the scale drawing if Trey changes the scale to 3 inches to 1 centimeter.

Part A.

What is the actual length of the microchip?

Part B.

What is the actual width of the microchip?

Part C.

Trey wants to change the scale of the drawing to 3 inches to 1 centimeter. Use the actual length of the microchip in Trey’s new scale drawing.

Part D.

Use the Actual Width from Part B to find the width of the microchip in Trey’s new scale drawing.

Part E.
What is the ratio of a drawing measurement from the original scale to the corresponding drawing measurement in the new scale? Show calculations for both length and width.

Part F.
In this activity, the scale drawing is larger than the actual microchip. How can you tell whether a scale drawing is smaller or larger than the actual object?

THANK YOU SO MUCH AND HAVE A GREAT DAY ! :)

Sagot :

Answer:

One inch represented 3 feet in the first scale, but now 1 inch now represents 4 feet in the second scale.

Step-by-step explanation:

Melanieq2017

Answer:

PART A : This formula shows how to find the actual length of the microchip:

actual length = scale length × reciprocal of scale factor.

The scale is 2 inches to 1 centimeter, so the scale factor is . 2in/1cm  The reciprocal of the scale factor is . 1cm/2in The length of the chip in the scale drawing is 6 inches.

To find the actual length of the microchip, substitute the values into the formula:

actual length  =  scale length × reciprocal of scale factor

= 6 in.  x  (1cm/2in)

= 3 cm

The actual length of the microchip is 3 centimeters.

PART B:

The scale is 2 inches to 1 centimeter, so the scale factor is .2in/1cm The reciprocal of the scale factor is .1cm/2in The width of the chip in the scale drawing is 4 inches.

To find the actual width of the microchip, substitute the values into the formula:

actual width  = scale width × reciprocal of scale factor

= 4 in. x  (1cm/2in)

= 2 cm

The actual width of the microchip is 2 centimeters.

PART C:

The new scale is 3 inches to 1 centimeter, so the new scale factor is . 3in/ 1cm The actual microchip is 3 centimeters long. Substitute these values into the following equation to find the scale length:

scale length = actual length × scale factor

= 3 cm  x (3in/1cm)

= 9 in.

The length of the microchip in the new scale drawing is 9 inches.

PART D:

The width of the microchip in the new scale drawing is 6 inches.

PART E:

In the original scale drawing, the microchip was 6 inches long. In the new scale drawing, the microchip is 9 inches long. Set up the ratio:

ratio .  6in/9 in 3in/2in

In the original scale drawing, the microchip was 4 inches wide. In the new scale drawing, the microchip is 6 inches wide. Set up the ratio:

ratio .  4in/6in  2in/3in

The ratio of the original scale drawing measurements to the new scale drawing measurements is 2 inches to 3 inches.

PART F:

If a scaled measurement is greater than the actual measurement it represents, then the scale drawing is larger than the actual object.

If a scaled measurement is less than the actual measurement it represents, then the scale drawing is smaller than the actual object.

PLEASE GIVE ME BRAINLIEST :))

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