Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Calculate the momentum of a 1,500 kg car traveling at 6 m/s.
A military airplane sometimes needs to refuel in mid-air, and another plane flies above it to add the fuel. If a plane with a mass of 7,800 kg is traveling with a velocity of 30 m/s and refuels by adding an additional 800 kg of jet fuel, what will its new velocity be? (Hint: This is a multi-step problem).

Sagot :

rafaleo84

Answer:

See the answers below.

Explanation:

Momentum is defined as the product of mass by velocity, in this way we have the following equation.

[tex]P=m*v[/tex]

where:

P = momemtum [kg*m/s]

m = mass = 1500 [kg]

v = velocity = 6 [m/s]

[tex]P = 1500*6\\P=9000 [kg*m/s][/tex]

Now we have to calculate the momentum of the plane when it travels at 30 [m/s].

[tex]P_{airplane}=m_{plane}*v_{plane}\\P_{airplane}=7800*30\\P_{airplane}=234000[kg*m/s][/tex]

Now this same momentum must be conserved, in such a way that the mass is increased but the velocity must decrease for the momentum to be conserved.

[tex]P=m_{new}*v_{new}\\234000=(7800+800)*v_{new}\\234000=8600*v_{new}\\v_{new}=27.2[m/s][/tex]

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.