Answer:
Step-by-step explanation:
the question is asking for the length of the side labeled x
use Pythagoras' theorem to find that side
where c = x because c represents the hypotenuse in the theorem and x is on the hypotenuse in this problem
c = [tex]\sqrt{a^{2} + b^{2} }[/tex]
sooo plug in a = 14 and b = 10
c = [tex]\sqrt{14^{2} + 10^{2} }[/tex]
c = [tex]\sqrt{196+100}[/tex]
c = [tex]\sqrt{296}[/tex]
c= 17.20465..... ( that's the approx. length of side x in the problem )
since this is a right triangle we could use trigonometry to find the two angles use SOH CAH TOA to remember how those functions fit on the triangle.
Sin(Ф)=Opp/Hyp Cos(Ф)=Adj/Hyp Tan(Ф)=Opp/Adj
since we know the Hyp (hypotenuse) and the side adjacent will be the side with the 10 soooo...
Cos(Ф)=10/17.20465
Ф = arcCos(10/17.20465)
Ф = 54.4623° is the angle on the side with 10
the side with 14 then has an angle of 35.5376°
:)
