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If the electronnegavity difference between elements A and X is 0.8, the bond in AX will most likely be what?

Sagot :

quasarJose

Answer:

Polar covalent bond

Explanation:

When the electronegativity difference between two elements A and X is 0.8, the bond AX formed will most likely be a polar covalent bond.

A polar covalent bond is one whose electronegativity difference is between 0.5 and 2.1.

In such a bond type, we have heteronuclear species with one of the species having a higher electronegativity value.

  • When electronegativity difference is less than 0.5, a non-polar covalent bond forms.
  • If the value is greater than 2.1, an ionic bond will form.
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