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The time of flight for an object thrown from the rooftop of a tall building is 6.2 seconds. In terms of the initial launch velocity v,
and the angle of launch o, what equation gives you the maximum displacement of the object?

The Time Of Flight For An Object Thrown From The Rooftop Of A Tall Building Is 62 Seconds In Terms Of The Initial Launch Velocity V And The Angle Of Launch O W class=

Sagot :

lucic

Answer:

B . x= v*cos ∅* 6.2

Explanation:

Time of flight of a projectile motion is the time taken by the object to reach the surface from when it was projected.

In this case ;

Initial launch velocity = v

Angle of launch is =∅

Time of flight = 6.2 seconds

The formula for time of flight is;

T= 2*v*sin∅  / g

At time t the displacement components for x and y are;

x= v* t * cos ∅  ----------------i

and

y =u* t * sin ∅ - 1/2 g*t² ------------ii

Taking equation i for displacement of the object in the x component

x = v* t* cos ∅

x = v * cos ∅ * 6.2

x = 6.2* v * cos ∅

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