amiras
Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.


The time of flight for an object thrown from the rooftop of a tall building is 6.2 seconds. In terms of the initial launch velocity v,
and the angle of launch o, what equation gives you the maximum displacement of the object?

The Time Of Flight For An Object Thrown From The Rooftop Of A Tall Building Is 62 Seconds In Terms Of The Initial Launch Velocity V And The Angle Of Launch O W class=

Sagot :

lucic

Answer:

B . x= v*cos ∅* 6.2

Explanation:

Time of flight of a projectile motion is the time taken by the object to reach the surface from when it was projected.

In this case ;

Initial launch velocity = v

Angle of launch is =∅

Time of flight = 6.2 seconds

The formula for time of flight is;

T= 2*v*sin∅  / g

At time t the displacement components for x and y are;

x= v* t * cos ∅  ----------------i

and

y =u* t * sin ∅ - 1/2 g*t² ------------ii

Taking equation i for displacement of the object in the x component

x = v* t* cos ∅

x = v * cos ∅ * 6.2

x = 6.2* v * cos ∅

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.