SeniaM
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Find the product of the expression:
(3x^2) (5x^8) (6x^5)

Sagot :

absor201

Answer:

[tex]\left(3x^2\right)\left(5x^8\right)\left(6x^5\right)=90x^{15}[/tex]                  

Step-by-step explanation:

Given the expression

[tex]\left(3x^2\right)\left(5x^8\right)\left(6x^5\right)[/tex]

Apply the exponent rule:

[tex]a^b\cdot \:a^c=a^{b+c}[/tex]

so the expression becomes

[tex]\left(3x^2\right)\:\left(5x^8\right)\:\left(6x^5\right)=3\cdot \:\:5\cdot \:\:6x^{2+8+5}[/tex]

Add the exponent numbers: 2+8+5=15

                             [tex]=3\cdot \:5\cdot \:6x^{15}[/tex]

Multiply the numbers: 3×5×6=90

                             [tex]=90x^{15}[/tex]

Therefore, we conclude that:

[tex]\left(3x^2\right)\left(5x^8\right)\left(6x^5\right)=90x^{15}[/tex]                        

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