Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Complete question :
Ray starts walking to school at a rate of 2 mi/h. Ten minutes later, his sister runs after him with his lunch, averaging 6mi/h. Determine take it takes for sister to catch up
Answer:
5 minutes
Step-by-step explanation:
Ray's rate = 2mi/ hr
Time walked before sister starts = 10 minutes = (10/60) = 0.16667 hours
Hence, distance already covered = (rate * time) = (2 * 0.16667) = 0.3333 miles
To catchup :
Let t = Time taken to catch ; At t, distance covered must be the same ; thus ;
0.3333 + (2 * t) = 6 * t
0.3333 + 2t = 6t
0.3333 = 6t - 2t
0.3333 = 4t
t = 0.3333 / 4
t = 0.0833333 hours
t = 0.0833333 * 60 = 5 minutes
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.