Answer:
58[tex]\sqrt{65}[/tex]
Step-by-step explanation:
you can find the height of this trapezoid by using the pythagorean theorem where the hypotenuse is 18 and one leg is 8 (33-25)
let x = height
[tex]8^{2}[/tex] + [tex]x^{2}[/tex] = [tex]18^{2}[/tex]
[tex]x^{2}[/tex] = 324 - 64
[tex]x^{2}[/tex] = 260 therefore, x = [tex]\sqrt{260}[/tex]
[tex]\sqrt{260}[/tex] = [tex]\sqrt{4}[/tex]· [tex]\sqrt{65}[/tex] or 2[tex]\sqrt{65}[/tex]
A = [tex]\frac{1}{2}[/tex]h x (sum of the bases)
bases are 25 and 33
A = (2[tex]\sqrt{65}[/tex]) ÷ 2)58
