Subhambhai
Answered

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Ifa truck starts from rest and it has acceleration of 4 m/s for 5 second
calculate its final velocity. What will be the distance travelled by the track
during the time interval?
​

Sagot :

NusrathC

Answer:

Distance 50m

final velocity 20ms^-1

[tex]s = ut + \frac{1}{2} a {t}^{2} \\ = 0 \times t + \frac{1}{2} \times 4 \times {5}^{2} = 50m[/tex]

[tex]v = u + at \\ v = 0 + 4 \times 5 \\ v = 20ms^{ - 1} [/tex]

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