mgrsurjina000
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calculate the mass of 120cc nitrogen present at STP. how many number of molecules are present in it?​

Sagot :

boffeemadrid

Answer:

[tex]0.15008\ \text{g}[/tex]

[tex]3.23\times 10^{21}[/tex]

Explanation:

1 mol of nitrogen at STP = 22.4 L = 22400 cc

n = Mol of [tex]N_2[/tex] = [tex]\dfrac{120}{22400}=0.00536\ \text{mol}[/tex]

M = Molar mass of [tex]N_2[/tex] = [tex]28\ \text{g/mol}[/tex]

[tex]N_A[/tex] = Avogadro's number = [tex]6.022\times 10^{23}\ \text{mol}^{-1}[/tex]

Mass of [tex]N_2[/tex] is

[tex]m=nM\\\Rightarrow m=0.00536\times 28\\\Rightarrow m=0.15008\ \text{g}[/tex]

Mass of the nitrogen is [tex]0.15008\ \text{g}[/tex]

Number of molecules is given by

[tex]nN_A=0.00536\times 6.022\times 10^{23}=3.23\times 10^{21}\ \text{molecules}[/tex]

The number of molecules present in it are [tex]3.23\times 10^{21}[/tex]

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