mgrsurjina000
Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

calculate the mass of 120cc nitrogen present at STP. how many number of molecules are present in it?​

Sagot :

boffeemadrid

Answer:

[tex]0.15008\ \text{g}[/tex]

[tex]3.23\times 10^{21}[/tex]

Explanation:

1 mol of nitrogen at STP = 22.4 L = 22400 cc

n = Mol of [tex]N_2[/tex] = [tex]\dfrac{120}{22400}=0.00536\ \text{mol}[/tex]

M = Molar mass of [tex]N_2[/tex] = [tex]28\ \text{g/mol}[/tex]

[tex]N_A[/tex] = Avogadro's number = [tex]6.022\times 10^{23}\ \text{mol}^{-1}[/tex]

Mass of [tex]N_2[/tex] is

[tex]m=nM\\\Rightarrow m=0.00536\times 28\\\Rightarrow m=0.15008\ \text{g}[/tex]

Mass of the nitrogen is [tex]0.15008\ \text{g}[/tex]

Number of molecules is given by

[tex]nN_A=0.00536\times 6.022\times 10^{23}=3.23\times 10^{21}\ \text{molecules}[/tex]

The number of molecules present in it are [tex]3.23\times 10^{21}[/tex]

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.