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Sagot :
Answer:
C. 5, 12, 13
Step-by-step explanation:
A. 16, 32, 36
[tex]\sqrt{16^{2} +32^{2} } =\sqrt{256+1024} =\sqrt{1280} =16\sqrt{5} \\16\sqrt{5} \neq 36[/tex]
B. 6,7,8
[tex]\sqrt{6^{2} +7^{2} } =\sqrt{36+49} =\sqrt{85} \\\sqrt{85}\neq 8[/tex]
C. 5, 12, 13
[tex]\sqrt{5^{2} +12^{2} } =\sqrt{25+144} =\sqrt{169} =13\\13=13[/tex]
D. 8, 12, 16
[tex]\sqrt{8^{2} +12^{2} } =\sqrt{64+144} =\sqrt{208} =4\sqrt{13} \\4\sqrt{13}\neq 16[/tex]
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