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Please help almost due!!!!!!!!!!

Please Help Almost Due class=

Sagot :

Step-by-step explanation:

Let's finish strong! Maybe we'll have some time for some fun activities!

Let's start with angle B.

Remember that the internal angle of a triangle will always equal 180.

We have a rignt angle (90), a known angle (54), and unknown B.

We can establish a simple equation to solve for B.   [tex]B = 180 - 90 - 54[/tex]

33% done!

To solve for the other sides of the triangle, we'll need to use our trig functions! Boo! I know, but they are super handy! Let's see them in action.

Remember that ol' saying - some old hippy caught another hippy tripping on acid. SOH, CAH, TOA.

sin = opposite over hypotenuse, cos = adjacent over hypotenuse, tan = opposite over adjacent. [tex]tan(54) = a/23[/tex]

A little fancy calculator work and we're 66% done! whew!

If we know a and the third side as being 23, we can just use the Pythagorean theorem

[tex]c^2 = a^2 + b^2[/tex]

Done! Wow! That's feels good. Great job!