jaylencopeland01
Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Need Help ASAP !
Topic is trigonometric ratios.

Need Help ASAP Topic Is Trigonometric Ratios class=

Sagot :

MrRoyal

Answer:

[tex]\cos(T)[/tex] =[tex]\frac{\sqrt{15}}{5}[/tex]

Step-by-step explanation:

Given parameters.

[tex]TU = 4\sqrt 5[/tex]

[tex]SU = 4\sqrt 2[/tex]

[tex]ST = 4\sqrt 3[/tex]

Required

Determine [tex]\cos(T)[/tex]

Reference to [tex]\angle T[/tex], we have:

[tex]Opposite = 4\sqrt 2[/tex]

[tex]Adjacent = 4\sqrt 3[/tex]

[tex]Hypotenuse = 4\sqrt 5[/tex]

Apply trigonometry ratio of cosine

[tex]\cos(T)[/tex] [tex]= \frac{Adjacent}{Hypotenuse}[/tex]

Substitute values for Adjacent and Hypotenuse

[tex]\cos(T)[/tex] [tex]= \frac{4\sqrt 3}{4\sqrt 5}[/tex]

[tex]\cos(T)[/tex] [tex]= \frac{\sqrt 3}{\sqrt 5}[/tex]

Rationalize:

[tex]\cos(T)[/tex] [tex]= \frac{\sqrt 3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}[/tex]

[tex]\cos(T)[/tex] =[tex]\frac{\sqrt{15}}{5}[/tex]

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.