Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

The rectangle below has an area of 30k3 + 6k2.
The width of the rectangle is equal to the greatest common monomial factor of 30k3 and 6k2.
What is the length and width of the rectangle?

Sagot :

abidemiokin

Answer:

Width = 6k²

Length = 5k+1

Step-by-step explanation:

Given the area of a rectangle expressed as

A = 30k³ + 6k²

Get the greatest common factor

30k³ = (2 * 3 * k²) * k * 5

6k² = (2 * 3 * k²)

The common factor is the value in bracket i.e 2 * 3 * k² = 6k²

Width of the rectangle = 6k²

Get the length

A = LW

L = A/W

L = 30k³ + 6k²/6k²

L = 6k²(5k+1)/6k²

L = 5k + 1

Hence the length L = 5k+1

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.