Answered

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simplif[tex]\frac{x^{2} -8x+16}{x^{2} -7x+12}[/tex]y

Sagot :

Answer:

[tex]\frac{x^{2} -8x+16}{x^{2} -7x+12}=\frac{x^{2} -2.4.x+4^{2} }{x^{2} -3x-4x+12}=\frac{(x-4)^{2} }{x(x-3)-4(x-3)}=\frac{(x-4)^{2} }{(x-4)(x-3)}=\frac{x-4}{x-3}[/tex]

Step-by-step explanation:

sin270

Answer:

(x-4)/(x-3)

Step-by-step explanation:

[tex] {x}^{2} - 4x + 16 = (x - 4)(x - 4)[/tex]

[tex] {x}^{2} - 7x + 12 = (x - 4)(x - 3)[/tex]

Therefore, on dividing, result is (x-4)/(x-3)

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