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Two red and two blocks are placed into a bag you take one of the blocks out of the bag what is the probability the block is not blue

Sagot :

MrRoyal

Question:

Two red and two blue blocks....

Answer:

[tex]P(Not\ Blue) = \frac{1}{2}[/tex]

Step-by-step explanation:

Given

[tex]Red = 2[/tex]

[tex]Blue = 2[/tex]

Required

Probability of not selecting blue

First, we calculate the probability of selecting blue

[tex]P(Blue) = \frac{Blue}{Total}[/tex]

[tex]P(Blue) = \frac{2}{2+2}[/tex]

[tex]P(Blue) = \frac{2}{4}[/tex]

[tex]P(Blue) = \frac{1}{2}[/tex]

In probability:

Opposite probabilities sum up to 1 i.e.

[tex]P(Blue) + P(Not\ Blue) = 1[/tex]

This gives

[tex]\frac{1}{2} + P(Not\ Blue) = 1[/tex]

[tex]P(Not\ Blue) = 1 - \frac{1}{2}[/tex]

[tex]P(Not\ Blue) = \frac{2-1}{2}[/tex]

[tex]P(Not\ Blue) = \frac{1}{2}[/tex]

salair0589

Answer:

the answer would be 1/2 .,

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