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The graph of a linear equation has a slope of -2 and passes through point (-4, 3 ) what is the equation of the line

Sagot :

Answer:

(-4,3)=x1,y1

m=-2

we have

y-y1=m(x-x1)

y-3=-2(x+4)

y-3=2x+8

2x-y+11=0 is the eqn

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