Answered

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Please help, I don't know how to do this.
f(x)=(x+2)(x−4)
1) What are the zeros of the function?
2) What is the vertex of the parabola?

Sagot :

Answer:

(a) Zeroes of the function is -2,4.

(b) The vertex of the parabola is (1,-9).

Step-by-step explanation:

Given,

f(x)=(x+2)(x−4)

(a)To find the zeros of the function put f(x)=0.

(x+2)(x-4)=0

x+2 = 0        or      x-4 = 0

x = -2,4

Hence, zeroes of the function is -2,4.

(b)Now,

f(x)=(x+2)(x−4)

[tex]f(x)= x^2 -2x+1 -1-8[/tex]

[tex]f(x)= (x-1)^2-9[/tex]  .......(i)

We know that,

If [tex]f(x)=a(x-h)^2 +k[/tex] is the equation of parabola the (h,k) is the vertex of the parabola.

On comparing with equation (i), we get

h = 1

k = -9

Hence, the vertex of the parabola is (1,-9).

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