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Sagot :
Answer:
Considering the expression as
[tex]\dfrac{3}{4} \cdot [8x+16][/tex]
We have
[tex]\dfrac{3}{4} \cdot [8x+16] = \dfrac{3}{4} \cdot 8x + \dfrac{3}{4} \cdot 16 = \boxed{6x + 12}[/tex]
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