Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the

rhombus.

Sagot :

MrRoyal

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

[tex]JL = 48[/tex]

[tex]KM = 20[/tex]

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

[tex]P = 2\sqrt{(JL)^2 + (KM)^2}[/tex]

Substitute values for JL and KM

[tex]P = 2\sqrt{48^2 + 20^2}[/tex]

[tex]P = 2\sqrt{2304 +400}[/tex]

[tex]P = 2\sqrt{2704}[/tex]

[tex]P = 2 * 52[/tex]

[tex]P = 104[/tex]

Hence, the perimeter is 104 units

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.