Answered

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JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the

rhombus.

Sagot :

MrRoyal

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

[tex]JL = 48[/tex]

[tex]KM = 20[/tex]

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

[tex]P = 2\sqrt{(JL)^2 + (KM)^2}[/tex]

Substitute values for JL and KM

[tex]P = 2\sqrt{48^2 + 20^2}[/tex]

[tex]P = 2\sqrt{2304 +400}[/tex]

[tex]P = 2\sqrt{2704}[/tex]

[tex]P = 2 * 52[/tex]

[tex]P = 104[/tex]

Hence, the perimeter is 104 units

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