Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

What is the average rate of change for f(x) = 2 ^ x - 12 over the interval 4 <= x <= 8

Sagot :

absor201

Answer:

The everage rate of change over the interal 4 ≤ x ≤ 8 will be: 60

Step-by-step explanation:

Given the function

[tex]f\left(x\right)\:=\:2^x-\:12\:\:\:[/tex]

Interval : 4 ≤ x ≤ 8

or

Interval = [4, 8]

so

at x₁ = 4, f(x₁) = 2ˣ - 12 = 2⁴ - 12 = 16-12 = 4

at x₂ = 8,  f(x₂) = 2ˣ - 12  = 2⁸ - 12 = 256 - 12 = 244

Using the formula to determine the average rate of change over the interval  4 ≤ x ≤ 8 wil be:

Average rate = [f(x₂) - f(x₁)] / [ x₂ - x₁]

                      = [244 - 4] / [8-4]

                      = 240 / 4

                      = 60

Therefore, the everage rate of change over the interal 4 ≤ x ≤ 8 will be: 60

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.