Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

What is the average rate of change for f(x) = 2 ^ x - 12 over the interval 4 <= x <= 8

Sagot :

absor201

Answer:

The everage rate of change over the interal 4 ≤ x ≤ 8 will be: 60

Step-by-step explanation:

Given the function

[tex]f\left(x\right)\:=\:2^x-\:12\:\:\:[/tex]

Interval : 4 ≤ x ≤ 8

or

Interval = [4, 8]

so

at x₁ = 4, f(x₁) = 2ˣ - 12 = 2⁴ - 12 = 16-12 = 4

at x₂ = 8,  f(x₂) = 2ˣ - 12  = 2⁸ - 12 = 256 - 12 = 244

Using the formula to determine the average rate of change over the interval  4 ≤ x ≤ 8 wil be:

Average rate = [f(x₂) - f(x₁)] / [ x₂ - x₁]

                      = [244 - 4] / [8-4]

                      = 240 / 4

                      = 60

Therefore, the everage rate of change over the interal 4 ≤ x ≤ 8 will be: 60

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.