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A line has this equation: x + y = 6
Write an equation for the perpendicular line that goes through (5, 1).


A Line Has This Equation X Y 6 Write An Equation For The Perpendicular Line That Goes Through 5 1 class=

Sagot :

Answer:

the equation of the line will be: [tex]y=x-4[/tex]

Step-by-step explanation:

Equation of line: x + y = 6

We need to write an equation for the perpendicular line that goes through

(5, 1).

The equation will be in slope-intercept form [tex]y=mx+b[/tex] where m is slope and b is y-intercept

Finding Slope:

Equation of line given is: x+y=6

Writing it in slope-intercept form: [tex]y=-x+6[/tex]

The slope of this line is m = -1 (By comparing it with [tex]y=mx+b[/tex] we get m = -1)

Since the required line is perpendicular, their slopes will be opposite inverse of each other i.e. [tex]m_1=-\frac{1}{m_1}[/tex]

So, slope of required line will be: m=1

Now, using the point (5,1) and slope m=1 we can find y-intercept

[tex]y=mx+b\\1=1(5)+b\\1=5+b\\b=1-5\\b=-4[/tex]

So, we get y-intercept b = -4

Now, the equation of required line, having slope m=1 and y-intercept b = -4

[tex]y=mx+b\\y=1x-4[/tex]

So, the equation of the line will be: [tex]y=x-4[/tex]

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