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Answer:

a) Factors of [tex]x^2-2x=x(x-2)[/tex]

b) Factors of [tex]6x^2+12x=6x(x+2)[/tex]

c) Factors of [tex]3x^3-9x=3x(x^2-3)[/tex]

d) Factors of [tex]4x^2+28x^3=4x^2(1-7x)[/tex]

Step-by-step explanation:

We need to factorise

a) [tex]x^2-2x[/tex]

Taking x common:

[tex]x^2-2x\\=x(x-2)[/tex]

So factors of [tex]x^2-2x=x(x-2)[/tex]

b) [tex]6x^2+12x[/tex]

Taking 6x common:

[tex]6x^2+12x\\=6x(x+2)[/tex]

So factors of [tex]6x^2+12x=6x(x+2)[/tex]

c) [tex]3x^3-9x[/tex]

Taking 3x common:

[tex]3x^3-9x\\=3x(x^2-3)[/tex]

So factors of [tex]3x^3-9x=3x(x^2-3)[/tex]

d) [tex]4x^2+28x^3[/tex]

Taking 4x common

[tex]4x^2+28x^3\\=4x^2(1+7x)[/tex]

So factors of [tex]4x^2+28x^3=4x^2(1-7x)[/tex]

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