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A football quarterback throws a 0.408 kg football for a long pass. While in the motion of throwing, the quarterback moves the ball 1.909 m, starting from rest, and completes the motion in 0.439 s. Assuming the acceleration is constant, what force does the quarterback apply to the ball during the pass?

Sagot :

whitneytr12

Answer:

The quarterback applies a force of 8.08 N to the ball during the pass.  

Explanation:

To find the force we need to calculate the acceleration first so we can use the following equation:

[tex] F = ma [/tex]                        

Now, we can calculate the acceleration as follows:

[tex] x_{f} = x_{0} + v_{0}t + \frac{1}{2}at^{2} [/tex]    

Since the ball starts from rest [tex]v_{0} = 0[/tex] and [tex]x_{0} = 0[/tex]:

[tex] a = \frac{2*x_{f}}{t^{2}} = \frac{2*1.909 m}{(0.439 s)^{2}} = 19.81 m/s^{2} [/tex]

Now we can find the force:

[tex] F = 0.408 kg*19.81 m/s^{2} = 8.08 N [/tex]                

   

Therefore, the quarterback applies a force of 8.08 N to the ball during the pass.  

                                     

I hope it helps you!                                              

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