Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Let A,B, and C be square invertible matrices of the same size. If C has no eigenvalue equal to -1, then (AB + ACB)^-1 is equal to:

a. B^-1 (I + C)^-1*A^-1
b. (I + C)^-1*B^-1*A^-1
c. A^-1B*(I + C)^-1
d. (I + C)^-1*BA^-1

Sagot :

LammettHash

AB + ACB = A (B + CB) = A (I + C ) B

Taking the inverse gives

(A (I + C ) B)⁻¹ = B ⁻¹ (I + C )⁻¹ A ⁻¹

so the answer is (A)

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.