Answer:
1) [tex]kinectic energy=7.26*10^-^2^0J[/tex]
2) [tex]V= 2.0m/s[/tex]
3) [tex]T=3.5*10^3K[/tex]
4) The Molecules do not burn because of the presences of hydrogen bond in place
Explanation:
From the question we are told that
latent heat of vaporization for water at room temperature is 2430 J/g.
1)Generally in determining the molar mass of water evaporated we have that
-One mole (6.02 x 10. 23 molecules)
-Molar mass of water is 18.02 g/mol
Mathematically the mass of water is give as
[tex]M=\frac{18.02}{6.02*10^-^2^6}[/tex]
[tex]M=3*10^-^2^3g[/tex]
Therefore
[tex]kinectic energy=2430J/g*3*10^-^2^3g[/tex]
[tex]kinectic energy=7.26*10^-^2^0J[/tex]
b)Generally the evaporation speed V is given as[tex]V= \sqrt{\frac{K.E*2}{m} }[/tex]
Mathematically derived from the equation
[tex]\frac{1}{2} mv^2 =K.E[/tex]
To Give
[tex]V= \sqrt{\frac{K.E*2}{m} }[/tex]
[tex]V= \sqrt{\frac{7.26*10^-^2^0J*2}{3*10^-^2^3g} }[/tex]
[tex]V= 2.0m/s[/tex]
c)Generally the equation for velocity [tex]Vrms=\sqrt{\frac{3RT}{M} }[/tex]
Therefore
Effective temperature T is given by
[tex]T=\frac{\sqrt{v}*m}{R}[/tex]
where
[tex]T=\frac{\sqrt{2.0m/s}*6.02*10^-^2^6}{0.082057 L atm mol-1K-1}[/tex]
[tex]T=3.5*10^3K[/tex]
4) The Molecules do not burn because of the presences of hydrogen bond in place
