Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Steph makes 90\%90%90, percent of the free throws she attempts. She is going to shoot 333 free throws. Assume that the results of free throws are independent from each other. Let XXX represent the number of free throws she makes.
Find the probability that Steph makes exactly 111 of the 333 free throws.

Sagot :

Answer:

0.972

Step-by-step explanation:

TI-84

fichoh

Using the concept of binomial probability, the probability of making exactly 11 throws is [tex]6.073 \times 10^{-15} [/tex]

Recall :

  • P(x = x) = nCx * p^x * q^(n-x)
  • p = probability of success = 0.9
  • n = number of trials = 33
  • q = 1 - p = 0.1

The probability of making exactly 11 throws can be defined thus :

  • P(X = 11) = 33C11 * 0.9^11 * 0.1^22

Using a binomial probability calculator :

P(X = 11) = [tex]6.073 \times 10^{-15} [/tex]

Therefore, the probability is [tex]6.073 \times 10^{-15} [/tex]

Learn more : brainly.com/question

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.