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Sagot :
Using the concept of binomial probability, the probability of making exactly 11 throws is [tex]6.073 \times 10^{-15} [/tex]
Recall :
- P(x = x) = nCx * p^x * q^(n-x)
- p = probability of success = 0.9
- n = number of trials = 33
- q = 1 - p = 0.1
The probability of making exactly 11 throws can be defined thus :
- P(X = 11) = 33C11 * 0.9^11 * 0.1^22
Using a binomial probability calculator :
P(X = 11) = [tex]6.073 \times 10^{-15} [/tex]
Therefore, the probability is [tex]6.073 \times 10^{-15} [/tex]
Learn more : brainly.com/question
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