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When an object is dropped from a point above the ground the amount of time it takes to hit the ground is given by the equation [tex]t=\sqrt{\frac{2d}{9.8} }[/tex] where d is the distance above the ground, in meters, and t is given in seconds.


If you need something to fall for exactly 1.5 seconds, how high should it be when it is dropped? Round your answer to the nearest tenth (one decimal place)