Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Can someone help me please?


Can Someone Help Me Please class=

Sagot :

Answer:

[tex]x=\sqrt{12}[/tex]

Step-by-step explanation:

The Pythagorean theorem states that [tex]a^2+b^2=c^2[/tex] in a right triangle where c is the longest side. To solve for x, we plug in the side lengths given as a and c.

[tex]a^2+b^2=c^2\\2^2+x^2=4^2[/tex]

Move 2² to the other side to isolate b²

[tex]x^2=4^2-2^2[/tex]

Square root both sides to isolate b

[tex]x=\sqrt{4^2-2^2}\\x=\sqrt{16-4} \\x=\sqrt{12}[/tex]

I hope this helps!