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A line perpendicular to y=2/5x+1

Sagot :

Answer:

        y = -⁵/₂x + b

Step-by-step explanation:

y=m₁x+b₁   ⊥   y=m₂x+b₂   ⇔    m₁×m₂ = -1

{Two lines are perpendicular if the product of theirs slopes is equal -1}

y = ²/₅x + 1    ⇒     m₁ =  ²/₅

²/₅m₂ = -1        ⇒   m₂ = -⁵/₂

So, any line with slope m =  -⁵/₂ will be perpendicular to y = ²/₅x + 1  

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