lana6795
Answered

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Please anyone I’ll mark as a branlist

Please Anyone Ill Mark As A Branlist class=

Sagot :

rebeccarayshma

Answer:

the first option is the answer, r = √6

Step-by-step explanation:

[tex]hypotenuse = \sqrt{opposite {}^{2} + adjacent {}^{2} } [/tex]

hypotenuse = q = √12

adjacent = p = √6

opposite = r

substitute the values into the hypotenuse formula

[tex]q = \sqrt{r {}^{2} + p {}^{2} } [/tex]

[tex] \sqrt{12} = \sqrt{r {}^{2} + ( \sqrt{6} ) {}^{2} } [/tex]

[tex]( \sqrt{12} ) {}^{2} = r {}^{2} +6[/tex]

[tex]12 = r {}^{2} + 6[/tex]

[tex]12 - 6 = r {}^{2} [/tex]

[tex]6 = r {}^{2} [/tex]

[tex] \sqrt{6} = r[/tex]

[tex]r = \sqrt{6} [/tex]

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