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Given KW is perpendicular to JO, JP is perpendicular to KO, KN intersects with JP=Q. Prove that triangle OKW ~ triangle OJP

Sagot :

Supernova11

Answer:

Proved

Step-by-step explanation:

m∠JPO  = 90  =  m∠OWK, and angle O is common between both triangles [reflexive property]. Therefore by Rule AA, ΔOKW~ΔOJP

View image Supernova11

Triangle OKW similar to triangle OJP by angle-angle or AA or ΔOKW ~ ΔOJP by AA.

What is the similarity law for triangles?

It is defined as the law to prove that the two triangles have the same shape, but it is not compulsory to have the same size. The ratio of the corresponding sides is in the same proportions and the corresponding angles are congruent.

Please refer to the attached picture for the diagram.

We have:

KW is perpendicular to JO, JP is perpendicular to KO.

KN intersects with JP=Q.

From the figure:

Angle JPO =Angle OWK = 90 degrees

By using the reflexive property:

Angle O = Angle O

Thus, triangle OKW similar to triangle OJP by angle-angle or AA or ΔOKW ~ ΔOJP by AA.

Learn more about the similarity of triangles here:

brainly.com/question/8045819

#SPJ2

View image maheshpatelvVT
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