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A bag contains 18 balls to green five black eight blue one brown one red and one white if 17 balls of a move from the bag at random what is the probability that a brown ball has been removed

Sagot :

Answer:

[tex]P(Brown) = 0.0556[/tex] or [tex]P(Brown) = \frac{1}{18}[/tex]

Step-by-step explanation:

Given

[tex]Total = 18[/tex]

[tex]Green = 2[/tex]

[tex]Black = 5[/tex]

[tex]Blue = 8[/tex]

[tex]Brown = 1[/tex]

[tex]Red = 1[/tex]

[tex]White = 1[/tex]

Required

Determine the probability of selecting a brown ball

This is calculated as thus:

[tex]P(Brown) = \frac{Brown}{Total}[/tex]

Substitute values for Brown and Total

[tex]P(Brown) = \frac{1}{18}[/tex]

The answer can be in fraction or solved further as;

[tex]P(Brown) = 0.0556[/tex]

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