Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A tennis ball launcher works by using a spring to

propel the ball forward.

One model of tennis ball launcher has

advertised that it is capable of imparting

15,000 J of kinetic energy to a 0.5 kg ball

initially at rest. A student carefully measures the

compression of the spring to be 0.10 m.

What is the value of the spring constant for the

tennis ball launcher according to the data

provided?

Sagot :

samuelonum1

Answer:

3MN/m

Explanation:

Step one:

given data

Kinetic Energy KE=15,000J  

mass m= 0.5kg

compression x= 0.1m

Step two:

The expression for the energy stored in spring is

[tex]KE= 1/2ke^2\\\\15000=1/2 *k*0.1^2\\\\15000=1/2*k*0.01\\\\15000=0.005k\\\\[/tex]

divide both sides by

0.005

[tex]k= 15000/0.005\\\\k=3000000\\\\k= 3MN/m[/tex]

temdan2001

From conservation of energy, the value of the spring constant for the tennis ball launcher according to the data is 3 x [tex]10^{6}[/tex] Nm

The work done by a  tennis ball launcher by using a spring to propel the ball forward is equal to the kinetic energy which is 15,000 Joule. That is,

W = K.E

The given parameters are:

K.E = 15,000 J

Mass m = 0.5 kg

compression x = 0.1 m

The elastic potential energy on the spring will be equal to the work done by the tennis ball launcher. That is,

E = W

since W = K.E

E = K.E

1/2k[tex]x^{2}[/tex] = 1/2m[tex]v^{2}[/tex] = 15,000

1/2k[tex]x^{2}[/tex] = 15000

Substitute for 0.1 for x

1/2 K ([tex]0.1^{2}[/tex]) = 15000

[tex]0.1^{2}[/tex] K = 30000

K = 30000/0.01

K = 3 x [tex]10^{6}[/tex] Nm

Therefore,  the value of the spring constant for the tennis ball launcher according to the data is 3 x [tex]10^{6}[/tex] Nm

Learn more about Elasticity here: https://brainly.com/question/9821607

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.