Answered

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A light bulb consumes energy at a rate of 80

joules per second . How long in

seconds will it take for the light bulb to consume 2.30 ~ 105

in energy?

Sagot :

Eduard22sly

Answer:

2875 s

Explanation:

From the question given above, the following data were obtained:

Power (P) = 80 J/s

Energy (E) = 2.3×10⁵ J

Time (t) = ?

Power can simply be defined as the rate at which energy is used. Mathematically, power is expressed as:

Power = Energy / time

P = E/t

With the above formula, we can obtain the time taken for the bulb to consume 2.3×10⁵ J. This can be obtained as follow:

Power (P) = 80 J/s

Energy (E) = 2.3×10⁵ J

Time (t) = ?

Power = Energy / time

P = E/t

80 = 2.3×10⁵ /t

Cross multiply

80 × t = 2.3×10⁵

Divide both side by 80

t = 2.3×10⁵ / 80

t = 2875 s

Therefore, it will take 2875 s for the bulb to consume 2.3×10⁵ J of energy.

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