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A homeowner stays in a single location for an average of 20 years with a standard deviation of 5.7 years. What are the chances that someone lives in their home for 40 years or more?

Sagot :

Answer:

The Probability that someone lives in their home for 40 years or more

[tex]P(X\geq 40 ) = P( Z\geq3.50 )[/tex] = 0.0002

Step-by-step explanation:

Explanation:-

Given mean of the Population = 20 years

The standard deviation of the Population = 5.7 years

Let 'X' be the random variable in normal distribution

[tex]Z = \frac{x-mean }{S.D} = \frac{40-20}{5.7} = 3.508[/tex]

The Probability that someone lives in their home for 40 years or more

[tex]P(X\geq 40 ) = P( Z\geq3.50 )[/tex]

                 =  1 - P( Z< 3.50)

                = 1 - ( 0.5 + A(3.50)

                = 0.5 - 0.4998     ( from normal table )

               = 0.0002