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Which is the correct way to model the equation 5 x + 6 = 4 x + (negative 3) using algebra tiles? 5 positive x-tiles and 6 positive unit tiles on the left side; 4 positive x-tiles and 3 negative unit tiles on the right side 6 positive x-tiles and 5 positive unit tiles on the left side; 3 negative x-tiles and 4 positive unit tiles on the right side 5 positive x-tiles and 6 negative unit tiles on the left side; 4 positive x-tiles and 3 negative unit tiles on the right side 5 positive x-tiles and 6 positive unit tiles on the left side; 4 positive x-tiles and 3 positive unit tiles on the right side

Sagot :

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[tex]\huge\underline{\sf{\red{Problem:}}}[/tex]

  • Which is the correct way to model the equation 5 x + 6 = 4 x + ( -3 ) using algebra tiles?

[tex]\huge\underline{\sf{\red{Choices:}}}[/tex]

  • A.).5 positive x-tiles and 6 positive unit tiles on the left side; 4 positive x-tiles and 3 negative unit tiles on the right side.

  • B.) 6 positive x-tiles and 5 positive unit tiles on the left side; 3 negative x-tiles and 4 positive unit tiles on the right side

  • C.) 5 positive x-tiles and 6 negative unit tiles on the left side; 4 positive x-tiles and 3 negative unit tiles on the right side

  • D.) 5 positive x-tiles and 6 positive unit tiles on the left side; 4 positive x-tiles and 3 positive unit tiles on the right side

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

  • A.).5 positive x-tiles and 6 positive unit tiles on the left side; 4 positive x-tiles and 3 negative unit tiles on the right side.

[tex]\huge\underline{\sf{\red{Explanation:}}}[/tex]

  • To use algebra tiles to model an equation, we place the relevant number of variable rectangle tiles and number square tiles for the left side of the equation and for the right side of the equation. Then we play around with our tiles so that we end up with the rectangle tiles by themselves on one side.

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