Answer:
The line equation of the line is:
- [tex]y=-\frac{3}{8}x+3[/tex]
Step-by-step explanation:
Given the two points
Finding the slope between (0,3) and (8,0)
[tex]\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\left(x_1,\:y_1\right)=\left(0,\:3\right),\:\left(x_2,\:y_2\right)=\left(8,\:0\right)[/tex]
[tex]m=\frac{0-3}{8-0}[/tex]
[tex]m=-\frac{3}{8}[/tex]
Therefore, the slope of the line: m = -3/8
Using the point-slope form of the line equation
[tex]y-y_1=m\left(x-x_1\right)[/tex]
where m is the slope of the line and (x₁, y₁) is the point
substituting the values m = -3/8 and the point (0,3)
[tex]y-3=-\frac{3}{8}\left(x-0\right)[/tex]
[tex]y-3=-\frac{3}{8}x[/tex]
Add 3 to both sides
[tex]y-3+3=-\frac{3}{8}x+3[/tex]
Simplify
[tex]y=-\frac{3}{8}x+3[/tex]
Therefore, the line equation of the line is:
- [tex]y=-\frac{3}{8}x+3[/tex]
