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The diagram shows two squares constructed on the sides of a rectangle. Write an expression for the area of Square C in terms of the areas of Square A and Rectangle B. Then simplify to find the area. (N RN.1.1-2 HELP PLSSS

The Diagram Shows Two Squares Constructed On The Sides Of A Rectangle Write An Expression For The Area Of Square C In Terms Of The Areas Of Square A And Rectang class=

Sagot :

Step-by-step explanation:

Since area of Square A = 7 ft²,

Side length of Square A = √7 ft.

Length of Rectangle B = √7 ft

Width of Rectangle B = 4/√7 ft

Hence Area of Square C

= (4)² / (√7)² ft² = 16/7 ft².

The area of Square C is the square of the height of the Rectangle B.

Correct responses:

  • [tex]\underline{Area \ of \ square \ C = \dfrac{\left(Area \ of \ Rectangle \ B \right)^2}{Area \ of \ Square \, A} }[/tex]

  • [tex]Area \ of \ square \ C = \underline{\dfrac{16}{7}} \, ft.^2[/tex]

Methods used for finding the area of Square C

The given area of square A = 7 ft.²

The given area of rectangle, B = 4 ft.²

Let s represent the side length of square C and let S represent the side length of square A, we have;

Area of rectangle B = S × s = S·s

Area of square A = S × S = S²

Area of square C = s × s = s²

[tex]\mathbf{\dfrac{(Area \ of \ rectangle \ B)^2}{Area \ of \ square \ A } } = \dfrac{\left(S \cdot s \right)^2}{S^2} = \dfrac{S^2 \cdot s^2}{S^2} = s^2 = Area \ of \ square \ C[/tex]

Therefore, the expression for the area of Square C in terms of the area

of Square A and Rectangle B is presented as follows;

  • [tex]\underline{Area \ of \ Square \ C = \dfrac{ \left (Area \ of \ rectangle \ B \right)^2}{\left(Area \ of \ square \ A\right)}}[/tex]

Which gives;

  • [tex]\underline{Area \ of \ square \ C = \dfrac{\left(4 \, ft.^2 \right)^2}{7 \, ft.^2}}[/tex]

By simplification, we have;

[tex]\mathbf{\dfrac{\left(4 \, ft.^2 \right)^2}{7 \, ft.^2}} = \dfrac{16}{4} \, ft.^2[/tex]

  • [tex]Area \ of \ square \ C = \underline{ \dfrac{16}{7}} \, ft.^2[/tex]

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