Answer:
250 of 65% acid
100 gallons of 30% acid
Really sorry if this is incorrect, I had this question on my Lesson 16 test, and I don't know if it's correct or not...
Following are the calculation to the given question:
Assuming
x=The number of gallons of pure acid [tex](50\%)[/tex]
y = The number of liters of pure acid at [tex](80\%)[/tex] a concentration
[tex]\to x+y = 350[/tex]
The total quantity of gallons of each of the two types of pure acids............(1)
[tex]\to 0.65x+0.30y = 0.55(x+y)[/tex]
the mixture's acidity
[tex]\to 0.65x+0.30y = 0.55(350)\\\\\to 0.65x+0.30y = 192.5 ..........(2)[/tex]
So we have two equations and two variables to work with.
[tex]\to x+y = 350\\\\\to 0.65x+0.30y = 192[/tex]
multiply the first equation by [tex]0.30[/tex]
[tex]\to 0.30x+0.30y = 105\\\\\to 0.65x+0.30y = 192[/tex]
Subtract the second equation from the first
[tex]\to 0.35x = 87\\\\\to x = 248. 57 \approx 248 \ gallons\\\\ \to y = 350-248 = 102\ gallons\\\\[/tex]
As a result, we'll need 248 gallons of 65% pure acid and 102 gallons of 30% pure acid.
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