Answer:
The equation of line that passes through point (2,-1) and has a slope of -3 is [tex]\mathbf{y=-3x+5}[/tex]
Option A is correct.
Step-by-step explanation:
We need to write equation of line that passes through point (2,-1) and has a slope of -3
The equation is written in slope-intercept form: [tex]y=mx+b[/tex] where m is slope and b is y-intercept.
We are given slope: m = -3
We need to find y-intercept (b)
Using the point (2,-1) and slope m=-3, we can find y-intercept
[tex]y=mx+b\\-1=-3(2)+b\\-1=-6+b\\b=-1+6\\b=5[/tex]
So, we get y-intercept b = 5
Now, the required equation having slope m =-3 and y-intercept b = 5 will be:
[tex]y=mx+b\\y=-3x+5[/tex]
So, the equation of line that passes through point (2,-1) and has a slope of -3 is [tex]\mathbf{y=-3x+5}[/tex]
Option A is correct.
